A) \[\frac{2}{3}\Omega \]
B) \[\frac{1}{3}\Omega \]
C) \[2\Omega \]
D) \[5\Omega \]
Correct Answer: D
Solution :
[d] In the given circuit, three resistances each of \[3\Omega \]. are in parallel. Their equivalent resistance is given by, \[\frac{1}{r}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}\] or \[r=1\Omega \] The combination is in series with other two resistances each of \[2\Omega \] So, the equivalent resistance is, \[R=(2+1+2)\Omega =5\Omega \]
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