A) 2
B) 3
C) 4
D) 5
Correct Answer: A
Solution :
[a] 1 man's 1 day work =\[\frac{1}{108}\] 12 men's 6 days work \[=\frac{1}{9}\times 6=2/3\] Remaining work =1/3, men's 1 day work \[=\frac{1}{108}\times 18=\frac{1}{6}\] \[\therefore \,\,\frac{1}{3}\]of work 18 men will do in \[\frac{1}{3}\div \frac{1}{6}\]= 2 daysYou need to login to perform this action.
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