A) \[a+c=2b\]
B) \[{{b}^{2}}=ac\]
C) \[\frac{1}{a}+\frac{1}{c}=\frac{2}{b}\]
D) \[{{a}^{2}}+{{c}^{2}}=2{{b}^{2}}\]
Correct Answer: C
Solution :
[c] \[{{x}^{a}}={{y}^{b}}={{z}^{c}}=k\,(say)\] \[\Rightarrow \,\,x={{k}^{\frac{1}{a}}},y={{k}^{\frac{1}{b}}},z={{k}^{\frac{1}{c}}}\] \[{{y}^{2}}=zx\Rightarrow {{k}^{2/b}}={{k}^{1/c}}.{{k}^{1/a}}\] \[\Rightarrow \frac{2}{b}=\frac{1}{a}+\frac{1}{c}\]You need to login to perform this action.
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