A) Zero
B) E
C) \[\frac{E}{n}\]
D) \[\left( \frac{n-1}{n} \right)E\]
Correct Answer: A
Solution :
[a] The equivalent circuit of any one of the cells is given by, \[{{V}_{A}}-{{V}_{B}}=-E+Ir\] But \[I=\frac{nE}{nr}\] \[=\frac{E}{r}\] \[\therefore \,\,{{V}_{A}}-{{V}_{B}}=-E+\frac{E}{r}\times r\] \[=-\,E+E\] =0 So, potential difference across any one of the cells is zero.You need to login to perform this action.
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