A) \[\frac{M({{M}^{2}}-3)}{3}\]
B) \[{{M}^{3}}\]
C) \[{{M}^{3}}-3\]
D) \[M(4{{M}^{2}}-3)\]
Correct Answer: D
Solution :
[d] \[x+\frac{1}{x}=2\,\,M\] Average of \[{{x}^{3}}\] and \[{{x}^{-3}}=\frac{1}{2}\left( {{x}^{3}}+\frac{1}{{{x}^{3}}} \right)\] \[=\frac{1}{2}\left[ {{\left( x+\frac{1}{x} \right)}^{3}}-3\left( x+\frac{1}{x} \right) \right]\] \[=\frac{1}{2}[8{{M}^{3}}-6M]=M(4{{M}^{2}}-3)\]You need to login to perform this action.
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