A) 1
B) 2
C) \[2\sqrt{2}\]
D) \[3\sqrt{3}\]
Correct Answer: B
Solution :
[b] We have, \[x=2+1+2\sqrt{2}\] \[={{(\sqrt{2}+1)}^{2}}\] \[\Rightarrow \,\sqrt{x}=\sqrt{2}+1\] Also, \[\frac{1}{\sqrt{x}}=\sqrt{2}-1\] \[\therefore \,\,\sqrt{x}-\frac{1}{\sqrt{x}}=\sqrt{2}+1-\sqrt{2}+1\] = 2You need to login to perform this action.
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