A) \[\frac{3}{2}\Omega \]
B) \[2\Omega \]
C) \[4\Omega \]
D) \[8\Omega \]
Correct Answer: A
Solution :
[a] It involves a balanced wheatstone bridge circuit. This is equivalent to \[2\Omega \] So, the circuit reduces to The whole arrangement is equivalent to two resistances of values \[6\Omega \]. and \[2\Omega \]. in parallel. So. \[\frac{1}{R}=\frac{1}{2}+\frac{1}{6}\] \[=\frac{3+1}{6}\] \[=\frac{4}{6}\] \[\therefore R=\frac{3}{2}\Omega \]You need to login to perform this action.
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