A) 38
B) 34
C) \[38\sqrt{2}\]
D) \[36\sqrt{2}\]
Correct Answer: B
Solution :
[b] \[{{x}^{2}}+{{y}^{2}}={{(x+y)}^{2}}-2xy.\]Now, \[x+y=2,\] And \[x\times y=-1\] \[\therefore \,\,{{x}^{2}}+{{y}^{2}}=22-2(-1)=6\] \[{{x}^{4}}+{{y}^{4}}={{({{x}^{2}}+{{y}^{2}})}^{2}}-2{{x}^{2}}{{y}^{2}}\] \[=36-2=34\]You need to login to perform this action.
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