A) 1.45
B) 1.88
C) 2.9
D) 3.7
Correct Answer: C
Solution :
[c]\[{{x}^{Z}}={{y}^{2}}\,\,\,\,\Rightarrow \,\,\,{{10}^{0.48}}{{)}^{Z}}={{({{10}^{0.70}})}^{2}}\] \[\Rightarrow \,\,\,0.48Z=0.70\times 2\] \[\Rightarrow \,\,\,Z=\frac{140}{48}=2.9(approx)\]You need to login to perform this action.
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