A) \[T=2h/\upsilon \]
B) \[T=\sqrt{\frac{2h}{g}}+\frac{h}{\upsilon }\]
C) \[T=\sqrt{\frac{2h}{\upsilon }}+\frac{h}{g}\]
D) \[T=\sqrt{\frac{h}{2g}}+\frac{2h}{\upsilon }\]
Correct Answer: B
Solution :
[b] The stone falls with acceleration g while sound comes back with constant velocity v. We have, \[h=\frac{1}{2}g{{t}_{1}}^{2}\,\,and\,\,h=v{{t}_{2}}\] So, \[{{t}_{1}}+{{t}_{2}}=\sqrt{\frac{2h}{g}}+\frac{h}{v}\] \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,T=\sqrt{\frac{2h}{g}}+\frac{h}{v}\]You need to login to perform this action.
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