A) \[20{}^\circ \]
B) \[15{}^\circ \]
C) \[30{}^\circ \]
D) \[10{}^\circ \]
Correct Answer: B
Solution :
[b]\[\angle EDC=180{}^\circ -125{}^\circ -55{}^\circ =\angle CBA\] \[~\angle ACB=80{}^\circ ,\text{ }so\text{ }\angle CAB=180{}^\circ -55{}^\circ -80{}^\circ =45{}^\circ \]Also, \[\angle CAB\text{ }=\text{ }\angle AFB\text{ }+\text{ }\angle FBA\] \[\Rightarrow 45{}^\circ \text{ }=\text{ }\angle AFB\text{ }+\text{ }30{}^\circ \]which gives \[\angle AFB\text{ }=15{}^\circ \]
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