A) \[2\Omega \]
B) \[8\Omega \]
C) \[\frac{16}{3}\Omega \]
D) \[1\Omega \]
Correct Answer: D
Solution :
[d] \[1\,\Omega \] and \[1\,\Omega \] in series gives \[2\,\Omega \], which is in parallel with \[2\,\Omega \], so the equivalent resistance is \[1\,\Omega \] \[1\,\Omega \] again in series with \[1\,\Omega \]. gives \[2\,\Omega \], which is in parallel with \[2\,\Omega \], so the equivalent resistance is \[1\,\Omega \] Again \[1\,\Omega \] in series with \[1\,\Omega \], gives ,\[2\,\Omega \] which is in parallel with \[2\,\Omega \], hence the effective resistance across P and Q is \[1\,\Omega \]
You need to login to perform this action.
You will be redirected in
3 sec
