A) \[2{{a}^{2}}\]
B) \[-2{{a}^{3}}\]
C) 1
D) 0
Correct Answer: D
Solution :
[d] \[{{x}^{3}}=\left( a+\sqrt{{{a}^{2}}+{{b}^{3}}} \right)+\left( a-\sqrt{{{a}^{2}}+{{b}^{3}}} \right)\] \[+\text{ }3\text{ }\left( {{\text{a}}^{2}}-{{a}^{2}}+{{b}^{3}} \right).\text{ }x\] \[=2a-3b\,\,x\] \[\therefore \,\,{{x}^{3}}+3bx-2a=0\]You need to login to perform this action.
You will be redirected in
3 sec