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NTSE Sample Paper NTSE SAT Practice Test-20

  • question_answer
    If y = E (x) such that E (x) =\[\frac{px+q}{qx-p}\], then E(y) is equal to            

    A) x            

    B) \[\frac{x}{p}\]

    C) \[\frac{x}{q}\]                          

    D) \[\frac{x}{pq}\]

    Correct Answer: A

    Solution :

    [a] \[y=E(x)\,=\frac{px+q}{qx-p}.........(i)\] \[\Rightarrow \,\,y(qx-p)=px+q\] \[\Rightarrow \,\,x(yq-p)=yp+q\] \[\therefore \,\,\,=\frac{yp+q}{qx-p}\,\,\,.......(ii)\] Comparing (i) and (ii), clearly, y = x                    


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