A) \[v-\frac{g}{2}(2n+1)\]
B) \[v-\frac{g}{2}(2n-1)\]
C) \[\frac{v}{2}(2n-1)-g\]
D) \[g+\frac{v}{2}(2n-1)\]
Correct Answer: B
Solution :
[b] \[{{S}_{nth}}=u+\frac{a}{2}(2n-1)\] Here, u = v and \[a=-g\]You need to login to perform this action.
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