(i) Write the truth table for the following circuit. Name the equivalent gate that this circuit represents. |
(ii) Two identical amplifiers are connected one after the other in series (cascaded). The first amplifier has a voltage gain of 20. If the input signal is 0.01 V then calculate the output of AC signal. |
Answer:
(i) The logic combination of the given circuit is Truth Table
Hence, the given circuit performs the function of an AND gate. (ii) \[{{V}_{1}}={{V}_{2}}=20\] Input signal voltage, \[{{V}_{i}}=0.01V\] Output AC signal voltage, \[{{V}_{o}}=?\] The total voltage gain of two stage cascaded amplifier is given by the product of voltage gains of both the stages. Then, \[{{V}_{\text{gain}}}{{V}_{1}}\times {{V}_{2}}=20\times 20=400\] We have the relation, \[V=\frac{{{V}_{o}}}{{{V}_{i}}}\,\,or\,\,{{V}_{o}}={{V}_{gain}}\times {{V}_{i}}\] \[=400\times 0.01=4V\] Therefore, the output AC signal of the given amplifier is 4V.
A
B
\[O{{P}_{1}}\]
\[O{{P}_{2}}=Y\]
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