question_answer

Two identical loops, one of copper and the other of aluminium, are rotated with the same angular speed in the same magnetic field. Compare the induced emf in two coil loops.

Answer:

The induced emf in both the coils will be same as \[e=-(d\phi /dt)=BA\omega \,\,\sin \,\omega t.\] Since, \[B,\,\,A\] and \[\omega \] are same for both cases, induced emf will be same. \[\Rightarrow \]               \[\frac{{{e}_{c}}}{{{e}_{A}}}=\frac{1}{1}=1:1\]