Answer:
(i) \[{{10}^{-5}}A\] (ii) \[{{10}^{-\,2}}\,V\] (iii) \[2\times {{10}^{4}}\] Given, \[{{R}_{C}}=2k\,\Omega \] and \[{{I}_{C}}{{R}_{C}}=2\,V\] \[\Rightarrow \] \[{{I}_{C}}=\frac{2}{{{R}_{C}}}=\frac{2}{2000}={{10}^{-\,3}}A\] Given, \[\beta =100\] Current gain, \[\beta ={{I}_{C}}\,/\,{{I}_{b}}\]
Voltage gain, \[{{A}_{v}}=\frac{{{V}_{o}}}{{{V}_{i}}}=\frac{{{I}_{c}}{{R}_{c}}}{{{I}_{b}}{{R}_{c}}}=\frac{2}{{{10}^{-\,2}}}=200\] \[\therefore \] Power gain \[{{A}_{p}}=\beta \times {{A}_{v}}=100\times 200=2\times {{10}^{4}}\] (i) \[{{I}_{b}}=\frac{{{I}_{C}}}{\beta }=\frac{{{10}^{-\,3}}}{100}={{10}^{-\,5}}A\] (ii) Input voltage, \[{{V}_{i}}={{l}_{b}}{{R}_{b}}={{10}^{-\,5}}\times {{10}^{3}}={{10}^{-\,2}}V\] (iii) Power gain, \[{{A}_{p}}={{\beta }_{av}}\times {{A}_{v}}\]
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