Answer:
Here, Z = 35 A and R = 30 cm = 0.3 m \[\therefore \] \[B=\frac{{{\mu }_{0}}I}{2\pi R}=\frac{4\pi \times {{10}^{-7}}\times 35}{2\pi \times 0.3}=2.33\times {{10}^{-5}}T\]
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