Answer:
Given, power, P = 1W Zener breakdown voltage, \[{{v}_{z}}=5V\] Minimum voltage, \[{{V}_{min}}=3V\] Maximum voltage, \[{{V}_{\max }}=7V\] Current, \[{{l}_{z\max }}=\frac{P}{{{V}_{Z}}}=\frac{1}{5}=0.2A\] The value of R for safe operation, \[{{R}_{Z}}=\frac{{{V}_{\max }}-{{V}_{z}}}{{{l}_{z\max }}}=\frac{7-5}{0.20}=\frac{2}{0.2}\] \[{{R}_{z}}=10\,\Omega \]
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