| One pipe fills a water tank three times faster than another pipe. If the two pipes together can fill the empty tank in 36 min, then how much time will the slower pipe alone take to fill the tank? |
A) 1 h 21 min
B) 1 h 48 min
C) 2 h
D) 2 h 24 min
Correct Answer: D
Solution :
| Let second pipe take 3x min to fill a tank. |
| \[\therefore \] Time taken to fill a tank by first pipe is x min. |
| \[\therefore \] \[\frac{1}{x}+\frac{1}{3x}=\frac{1}{36}\]\[\Rightarrow \]\[\frac{3+1}{3x}=\frac{1}{36}\] |
| \[\Rightarrow \] \[x=\frac{4\times 36}{3}=48\] |
| Hence, time taken by second pipe \[=3\times 48\min \] |
| \[=144\min =2\,h\,24\min \] |
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