| Directions: What should come at the place of question mark (?) in the following questions? [IBPS (Clerk) 2015] |
| \[{{(32\times {{10}^{-5}})}^{2}}\times 64\div ({{2}^{16}}\times {{10}^{-4}})={{10}^{?}}\] |
A) 6
B) 10
C) \[-\,8\]
D) \[-\,6\]
E) \[-10\]
Correct Answer: D
Solution :
| \[{{(32\times {{10}^{-5}})}^{2}}\times 64\div ({{2}^{16}}\times {{10}^{-4}})={{10}^{?}}\] |
| \[\Rightarrow \] \[\frac{32\times 32\times {{10}^{-10}}\times 64}{{{2}^{16}}\times {{10}^{-4}}}={{10}^{?}}\] |
| \[\Rightarrow \] \[\frac{{{2}^{10}}\times {{10}^{-10}}\times {{2}^{6}}}{{{2}^{16}}\times {{10}^{-4}}}={{10}^{?}}\] |
| \[\Rightarrow \] \[\frac{{{2}^{16}}\times {{10}^{-10}}\times {{10}^{4}}}{{{2}^{16}}}={{10}^{?}}\] |
| \[\Rightarrow \] \[{{10}^{-6}}={{10}^{?}}\] |
| \[\therefore \] \[?=-\,6\] |
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