| Directions: In each of the following questions two equations I and II are given. You have to solve both the equations and find out values of x, y and give answer. [LIC (AAO) 2014] |
| I. \[\sqrt{(36)}x+\sqrt{64}=0\] |
| II. \[\sqrt{(81)}y+{{(4)}^{2}}=0\] |
A) If \[x>y\]
B) If \[x\le y\]
C) If \[x<y\]
D) If \[x\ge y\]
E) If relationship cannot be established
Correct Answer: A
Solution :
| I. \[\sqrt{36}x+\sqrt{64}=0\] |
| \[\Rightarrow \] \[6x+8=0\] |
| \[\Rightarrow \] \[x=\frac{-\,8}{6}\]\[\Rightarrow \]\[x=\frac{-\,4}{3}\] |
| II. \[\sqrt{81}y+{{4}^{2}}=0\] |
| \[\Rightarrow \] \[9y+16=0\]\[\Rightarrow \]\[y=\frac{-16}{9}\] |
| Hence, \[x>y\] |
You need to login to perform this action.
You will be redirected in
3 sec
