The perimeters of two similar triangles are 30 cm and 20 cm, respectively. If one side of the first triangle is 9 cm. Determine the corresponding side of the second triangle. |
A) 13.5 cm
B) 6 cm
C) 5 cm
D) 15 cm
Correct Answer: B
Solution :
By the property of triangle similarity, |
\[\frac{\operatorname{Perimeter}\,of\,first\,triangle}{\text{perimeter}\,\text{of}\,\text{second}\,\text{triangle }}=\frac{\text{Side}\,\text{of}\,\text{first}\,\text{triangle}}{\text{Side}\,\text{of}\,\text{second}\,\text{triangle}}\]Let side of second triangle be x cm. |
\[\Rightarrow \] \[\frac{30}{20}=\frac{9}{x}\]\[\Rightarrow \]\[30\times x=9\times 20\] |
\[\Rightarrow \] \[x=\frac{9\times 20}{30}=6\,cm\] |
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