Walking at 6/7th of his usual speed a man is 25 min too late. His usual time to cover this distance is |
A) 2 h 30 min
B) 2 h 15 min
C) 2 h 25 min
D) 2 h 10 min
Correct Answer: A
Solution :
Time and speed are inversely proportional. |
\[\therefore \] \[=\frac{7}{6}\times \]Usual time \[-\] Usual time = 25 min |
\[\Rightarrow \] Usual time \[\left( \frac{7}{6}-1 \right)=25\min \] |
\[\Rightarrow \] Usual time \[\times \frac{1}{6}=25\min \] |
\[\therefore \] Usual time \[=25\times 6=150\min =2\,h\,30\min \] |
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