| Ashok left from place A (towards place B) at 8 am and Rahul left from place B (towards place A) at 10 am. The distance between place A and place B is 637 km. If Ashok and Rahul are travelling at a uniform speed of 39 km/h and 47 km/h respectively, at what time will they meet? |
A) 5 : 30 pm
B) 4 : 30 pm
C) 5 : 00 pm
D) 4 : 00 pm
Correct Answer: B
Solution :
 |
| Distance covered by Ashok in |
| \[2h=2\times 39=78\,km.\] |
| Remaining distance \[=637-78=559km.\] |
| Time taken |
| \[\text{=}\,\,\frac{\text{Total}\,\text{distance}\,\text{to}\,\text{cover}}{\text{Relative}\,\,\text{velocity}}=\frac{559}{86}=6.5\,h\] |
| \[\therefore \] Meeting time \[=10am+6.5h=4:30\,pm\] |
You need to login to perform this action.
You will be redirected in
3 sec
