| Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 am and travels towards B at 20 km/h. Another train starts from B at 8 am and travels towards A at a speed of 25 km/h. At what time will they meet? [NICL (AO) 2014] |
A) 9 am
B) 11 am
C) 11: 30 am
D) 10 am
E) 12 : 30 pm
Correct Answer: D
Solution :
| Distance between station A and B = 110 km |
| Speed of train starting \[({{s}_{1}})\] from station A = 20 km/h |
| Speed of train starting \[({{s}_{2}})\] from station B = 25 km/h |
| Time difference (t) = 1 h |
| Time taken from A to meet the trains |
| \[=\left( \frac{d+{{s}_{2}}}{{{s}_{1}}+{{s}_{2}}} \right)=\left( \frac{110+25}{20+25} \right)=3\,h\] |
| So, time \[=7am+3h=10\,am\] |
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