| A and B can do a piece of work in 15 days. B and C can do the same work in 10 days and A and C can do the same in 12 days. Time taker by A, B and C together to do the job is |
A) 9 days
B) 8 days
C) 4 days
D) 5 days
Correct Answer: B
Solution :
| \[(A+B)'s\]one day work \[=\frac{1}{15}\] |
| \[(B+C)'s\] one day work \[=\frac{1}{10}\] |
| \[(A+C)'s\] one day work \[=\frac{1}{12}\] |
| \[\therefore \] \[2\,(A+B+C)=\frac{1}{15}+\frac{1}{10}+\frac{1}{12}\] |
| \[\Rightarrow \] \[2\,(A+B+C)=\frac{4+6+5}{60}=\frac{15}{60}\] |
| \[\Rightarrow \] \[2\,(A+B+C)=\frac{1}{4}\] |
| \[\Rightarrow \] \[A+B+C=\frac{1}{8}\] |
| \[\therefore \] A, B and C together will finish the work in 8 days. |
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