| A jogger running at 9 km/h alongside a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/h in the same direction. In how much time will the train pass the jogger? |
A) 70 s
B) 36 s
C) 56 s
D) 18 s
Correct Answer: B
Solution :
| Total speed of jogger and train |
| \[=45-9=36\,km/h\] |
| (because train and jogger is in same direction) |
| Total speeds = 36km/h \[=36\times \frac{5}{18}m/s=10\,m/s\] |
| \[\therefore \] Time taken by train to pass the jogger |
| \[=\frac{\text{Total}\,\text{distance}}{\text{Total}\,\text{speed}}=\frac{(120+240)}{10}=\frac{360}{10}s=36\,s\] |
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