| If the ordinate and abscissa of the point \[(k,\,\,2k-1)\] be equal, then the value of k is [SSC (CGL) 2014] |
A) \[-1\]
B) 1/2
C) 0
D) 1
Correct Answer: D
Solution :
| Given, ordinate and abscissa of the point are equal |
| \[k=2k-1\] |
| \[\Rightarrow \] \[2k-k=1\]\[\Rightarrow \]\[k=1\] |
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