question_answer

Let the least number of six digits which when divided by 4, 6, 10 and 15 leaves in each case same remainder 2 be N. The sum of digits in N is

A) 3                                 

B) 5

C) 4                                 

D) 6

Correct Answer: B

Solution :

Least six digit number is 100000.

LCM of 4, 6, 10, 15

\[\therefore \] LCM\[=2\times 2\times 3\times 5=60\]

LCM of 4, 6, 10, 15 = 60

\[\therefore \] Required number

\[=100000+(60-40)+2=100022\]

\[\therefore \] Sum of the digits of

\[=N=1+0+0+0+2+2=5\]