Let the least number of six digits which when divided by 4, 6, 10 and 15 leaves in each case same remainder 2 be N. The sum of digits in N is |
A) 3
B) 5
C) 4
D) 6
Correct Answer: B
Solution :
Least six digit number is 100000. |
LCM of 4, 6, 10, 15 |
\[\therefore \] LCM\[=2\times 2\times 3\times 5=60\] |
LCM of 4, 6, 10, 15 = 60 |
\[\therefore \] Required number |
\[=100000+(60-40)+2=100022\] |
\[\therefore \] Sum of the digits of |
\[=N=1+0+0+0+2+2=5\] |
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