| A's income is 10% more than B's income. How much per cent is B's income less than A's income? |
A) \[8\frac{1}{11}\]%
B) \[9\frac{1}{11}\]%
C) \[10\frac{1}{11}\]%
D) 12%
Correct Answer: B
Solution :
| Let Bs income be Rs. x. |
| Then, As income \[=x+\frac{10}{100}\times x=\frac{11x}{10}\] |
| Required percentage \[=\,\,\frac{\left( \frac{11x}{10}-x \right)}{\frac{11x}{10}}\times 100\] |
| \[=\,\,\frac{\frac{x}{10}}{\frac{11x}{10}}\times 100=\frac{100}{11}=9\frac{1}{11}\]% |
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