| A train, 240 m long crosses a man walking along the line in opposite direction at the rate of 3 km/h in 10 s. The speed of the train is [SSC (CGL) 2010] |
A) 63 km/h
B) 75 km/h
C) 83.4 km/h
D) 69 km/h
Correct Answer: C
Solution :
| Let speed of train = x km/h |
| \[\therefore \] \[(x+3)\times \frac{1000}{3600}=\frac{240}{10}\]\[\Rightarrow \,\]\[\frac{(x+3)\times 10}{36}=24\] |
| \[\Rightarrow \] \[10\,(x+3)=36\times 24\] |
| \[\Rightarrow \] \[x=83.4\,km/h\] |
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