| If \[9\sqrt{x}=\sqrt{12}+\sqrt{147},\] then x is equal to |
A) 2
B) 3
C) 4
D) 5
Correct Answer: B
Solution :
| \[9\sqrt{x}=\sqrt{12}+\sqrt{147}\] |
| \[\Rightarrow \] \[9\sqrt{x}=\sqrt{4\times 3}+\sqrt{49\times 3}\] |
| \[\Rightarrow \] \[9\sqrt{x}=\sqrt{3}\,(\sqrt{4}+\sqrt{49})\] |
| \[\Rightarrow \] \[9\sqrt{x}=\sqrt{3}\,(2+7)=9\sqrt{3}\]\[\Rightarrow \]\[\sqrt{x}=\sqrt{3}\] |
| \[\therefore \] \[x=3\] |
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