| In the given figure, AOB is a straight line. If \[\angle AOC=40{}^\circ ,\]\[\angle COD=4x{}^\circ \]and \[\angle BOD=3x{}^\circ ,\] then \[\angle COD\] is equal to |
 |
A) \[80{}^\circ \]
B) \[100{}^\circ \]
C) \[120{}^\circ \]
D) \[140{}^\circ \]
Correct Answer: A
Solution :
| \[4x+3x+40=180\]\[\Rightarrow \,\]\[7x=180-40\] |
| \[\Rightarrow \] \[7x=140\,\,\Rightarrow \,\,x=20{}^\circ \] |
| \[\therefore \] \[4x=80{}^\circ \] |
| \[\angle COD=4x=4\times 20=80{}^\circ \] |
You need to login to perform this action.
You will be redirected in
3 sec
