| Two numbers are in the ratio 3: 4. The product of their HCF and LCM is 2028. The sum of the numbers is |
A) 68
B) 72
C) 86
D) 91
Correct Answer: D
Solution :
| Let the number be 3x and 4x, respectively. |
| HCF \[\times \] LCM = First number \[\times \] Second number |
| \[\therefore \] \[2028=3x\times 4x\] |
| \[\Rightarrow \] \[{{x}^{2}}=\frac{2028}{12}=169\]\[\Rightarrow \]\[x=\sqrt{169}=13\] |
| \[\therefore \] Sum of numbers |
| \[=3x+4x=(3\times 13)+(4\times 13)=91\] |
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