There are two bags A and B. Bag A contains 6 red balls and 10 green balls and bag B contains 4 red balls and 6 green balls. One bag is selected at random. From the selected bag one ball is drawn at random. What is the probability that the ball drawn is red? [SBI (SO) 2016] |
A) \[\frac{27}{80}\]
B) \[\frac{31}{80}\]
C) \[\frac{39}{80}\]
D) \[\frac{20}{80}\]
E) \[\frac{33}{80}\]
Correct Answer: B
Solution :
Probability of drawing one red from bag \[A=\frac{6}{16}\] |
Probability of drawing one red from bag \[B=\frac{4}{10}\] |
Probability to select one bag \[=\frac{1}{2}\] |
\[\therefore \] Required probably \[=\frac{1}{2}\left( \frac{6}{16}+\frac{4}{10} \right)=\frac{31}{80}\] |
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