The least number which when divided by 24, 32 and 36 leaves the remainders 19, 27 and 31 respectively, is |
A) 283
B) 288
C) 293
D) 299
Correct Answer: A
Solution :
Here, \[24-19=5\] |
\[32-27=5\] |
and \[36-31=5\] |
LCM of (24, 32, 36) |
\[\therefore \] \[LCM=2\times 2\times 2\times 3\times 4\times 3=288\] |
\[\therefore \] Required number \[=288-5=283\] |
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