A train passes a platform 120 m long in 40 s and a boy standing on the platform in 30 s. The length of the train is |
A) 350 m
B) 360 m
C) 370 m
D) 380 m
Correct Answer: B
Solution :
Let the length of train be x m. |
Speed of train while crossing a platform |
\[=\frac{120+x}{40}m/s\] |
and speed of train while crossing a boy \[=\frac{x}{30}\] |
\[\therefore \] \[\frac{120+x}{40}=\frac{x}{30}\] |
\[\Rightarrow \] \[3600+30x=40x\] |
\[\Rightarrow \] \[x=360\,m\] |
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