Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer. |
A) If\[x>y\]
B) If \[x\ge y\]
C) If\[x<y\]
D) \[x\le y\]
E) If \[x=y\]or the relationship cannot be established
Correct Answer: B
Solution :
[b]\[{{x}^{2}}-72=x\] |
\[\Rightarrow \] \[{{x}^{2}}-x-72=0\] |
\[\Rightarrow \] \[{{x}^{2}}-9x+8x-72=0\] |
\[\Rightarrow \] \[x\,(x-9)+8\,(x-9)=0\] |
\[\Rightarrow \] \[(x-9)\,(x+8)=0\] |
\[\Rightarrow \] \[x=9,\]\[-\,8\] |
II. \[{{y}^{2}}=64\] |
\[\Rightarrow \]\[y=\sqrt{64}=\pm \,8\] |
\[\therefore \]\[x\ge y\] |
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