A) 48
B) 24
C) 32
D) 16
E) 36
Correct Answer: C
Solution :
| [c] Given, \[{{M}_{1}}=16,\]\[{{D}_{1}}=30,\]\[{{W}_{1}}=\frac{5}{9},\]\[{{M}_{2}}=x,\] |
| \[{{D}_{2}}=8,\]\[{{W}_{2}}=\frac{4}{9}\] |
| Using the formula, |
| \[\frac{{{M}_{1}}{{D}_{1}}}{{{W}_{1}}}=\frac{{{M}_{2}}{{D}_{2}}}{{{W}_{2}}}\]\[\Rightarrow \]\[\frac{16\times 30}{\frac{5}{9}}=\frac{x\times 8}{\frac{4}{9}}\] |
| \[\Rightarrow \] \[\Rightarrow \]\[\Rightarrow \]\[x=48\] |
| \[\therefore \] More men needed to hire to complete the project on time \[=48-16=32\]men |
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