A) 8 cm
B) 4 cm
C) 2 cm
D) 5 cm
Correct Answer: A
Solution :
[a] Height of the cylinder\[=\frac{2}{3}\times \][Diameter of sphere |
Height \[=\,\,\frac{4\times Radius}{3}\] [\[\because \]Diameter\[=2\times \]Radius] |
Volume of sphere \[=\frac{4}{3}\pi \times {{(8)}^{3}}\] |
Now, volume of cylinder \[=\pi {{r}^{2}}\times h=\pi \times {{r}^{2}}\times \frac{4r}{3}\] |
\[\Rightarrow \] \[\frac{4}{3}\times \pi \times {{(8)}^{3}}=\pi \times {{r}^{2}}\times \frac{4r}{3}\] |
\[\Rightarrow \] \[4\times 512=4{{r}^{3}}\]\[\Rightarrow \]\[r=8\,cm\] |
Alternate Method |
Height of the cylinder \[=\frac{4}{3}\times Radius\] |
Hence, radius of the sphere and cylinder are same i.e. 8 cm. |
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