A) 15.6 s
B) 16.8 s
C) 17.2 s
D) 18 s
Correct Answer: B
Solution :
[b] Given, length of first train = 110 m and Length of second train = 170 m Let the time taken to cross each other be t. \[\text{Speed}\,\text{of}\,\text{train}=\frac{\text{Sum}\,\text{of}\,\text{lengths}\,\,\text{of}\,\text{both}\,\,\text{trains}}{\text{Time}\,\text{taken}\,\text{to}\,\text{cross}\,\text{each}\,\text{other}}\] \[\Rightarrow \] \[\frac{60\times 5}{18}\,\,=\,\,\frac{110+170}{t}\] \[\Rightarrow \] \[\frac{60\times 5}{18}=\frac{280}{t}\] \[\therefore \] \[t=\frac{280\times 18}{60\times 5}=16.8\,\,s\]
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