A) 98 cm
B) 40 cm
C) 41 cm
D) 82 cm
Correct Answer: D
Solution :
[d] Let \[{{D}_{1}}=18\,cm\] and \[{{D}_{2}}=80\,cm\] \[\therefore \] \[{{R}_{1}}=9\,cm\,\]and \[{{R}_{2}}=40\,\,cm\,\] Area of new circle \[=\pi \,\{{{(9)}^{2}}+{{(40)}^{2}}\}\] \[\pi {{R}^{2}}=\pi \times 1681=\pi \times {{(41)}^{2}}\] \[\Rightarrow \] \[R=41\] \[\therefore \] \[D=2\times R=82\,\,cm\]
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