A) 120
B) 48
C) 40
D) 24
Correct Answer: D
Solution :
[d] for digit to be even, units digit will be even. From the given digits, only 2 and 6 satisfy condition. \[\therefore \] Units place will always be 2 or 6. Then, rest two places will be occupied by any of the four digits i.e. \[{}^{4}{{P}_{2}}=\frac{4!}{(4-2)!}=\frac{4\times 3\times 2}{2}=12\] \[\therefore \] Total even numbers formed by digits 1, 2, 5 and 6 \[=\,\,12\times 2=24\]
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