| There are three pipes in a tank, first pipe can fill \[\frac{1}{2}\] part of the tank in 1 h, second pipe can fill \[\frac{1}{3}\] part of tank in 1 h and third pipe is used to make the tank empty. All three pipes are opened together, then only \[\frac{7}{12}\]part of tank is filled in one hour. In what time can the third pipe emptied the whole tank? [SSC (CGL) 2006] |
A) 3 h
B) 4 h
C) 5 h
D) 6 h
Correct Answer: B
Solution :
| 1 h work of first pipe \[=\frac{1}{2}\] |
| 1 h work of second pipe \[=\frac{1}{3}\] |
| \[\therefore \] 1 h work of third pipe |
| \[=\frac{7}{12}-\frac{1}{3}-\frac{1}{2}=-\frac{3}{12}=-\frac{1}{4}\] |
| Hence, third pipe emptied the tank in 4 h. |
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