A bus started its journey from Ramgarh and reached Devgarh in 44 min at its average speed of 50 km/h. If the average speed of the bus is increased by 5 km/h, then how much time will it take to cover the same distance? |
[Corporation Bank (PO) 2010] |
A) 40 mm
B) 38 min
C) 36 min
D) 31 min
E) 49 min
Correct Answer: A
Solution :
Average speed of bus = 50 km/h |
and time taken \[=44\min =\frac{44}{60}\,\,h\] |
Distance between Ramgarh and Devgarh |
\[=50\times \frac{44}{60}\,\,km\] |
Now, new speed = 55 km/h |
\[\therefore \] Required time = |
\[=\frac{50\times 44}{60\times 55}\times 60\min =40\min \] |
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