| A train 240 m long crosses a man walking along the line in opposite direction at the rate of 3 km/h in 10 s. The speed of the train is [SSC (CGL) 2010] |
A) 63 m/s
B) 75 m/s
C) 83.4 m/s
D) 86.4 m/s
Correct Answer: C
Solution :
| Let speed of train be x m/s. |
| Then, \[(x+3)\times \frac{5}{18}=\frac{240}{10}\] |
| \[\Rightarrow \] \[x+3=\frac{24\times 18}{5}=86.4\] |
| \[\Rightarrow \] \[x=86.4-3\]\[\Rightarrow \]\[x=83.4\,m/s\] |
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