If \[\frac{x}{y}=\frac{4}{5},\]then the value of \[\left( \frac{4}{7}+\frac{2y-x}{2y+x} \right)\] is [SSC (10+2) 2014] |
A) \[\frac{3}{7}\]
B) \[\frac{8}{7}\]
C) 1
D) 2
Correct Answer: C
Solution :
\[x=\frac{4y}{5}\] |
Now, \[\left( \frac{4}{7}+\frac{2y-x}{2y+x} \right)=\left( \frac{4}{7}+\frac{2y-\frac{4y}{5}}{2y+\frac{4y}{5}} \right)\] |
\[=\frac{4}{7}+\frac{6y}{5}\times \frac{5}{14y}=\frac{7}{7}=1\] |
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